On Wed, 23 Jun 2010 09:40:09 +0200, "Christopher M. Nahler" <[email protected]> wrote: > I have problems using a signal. In the code below I create a QListWidget > where I would like to act upon doubleClicking an item. > > In the documentation I have found the signal "itemDoubleClicked". > (http://doc.qt.nokia.com/4.6/qlistwidget.html#itemDoubleClicked) > But somehow I am not using it right. What am I doing wrong? > > thanks in advance > Chris > > > > import sys > from PyQt4.QtCore import * > from PyQt4.QtGui import * > > itemList = ["One", > "Two", > "Three", > "Four", > "Five"] > > class ListDlg(QDialog): > > def __init__(self, name, parent=None): > super(ListDlg, self).__init__(parent) > > self.myList = QListWidget() > self.myList.addItems(itemList) > self.myList.setCurrentRow(0) > > layout = QHBoxLayout() > layout.addWidget(self.myList) > self.setLayout(layout) > self.connect(self.myList, SIGNAL("itemDoubleClicked(*item)"), > self.processItem) > > def processItem(self, item): > print(item.text()) > > if __name__ == "__main__": > app = QApplication(sys.argv) > form = ListDlg("Listdialog") > form.exec_()
The signal signature is "itemDoubleClicked(QListWidgetItem *)" Phil _______________________________________________ PyQt mailing list [email protected] http://www.riverbankcomputing.com/mailman/listinfo/pyqt
