thanks alot. understood the args format for the signal function now!
On 23.06.2010 10:51, Zoltan Szalai wrote:
use:
self.myList.itemDoubleClicked.connect(self.processItem)
or:
self.connect(self.myList, SIGNAL("itemDoubleClicked(QListWidgetItem
*)"), self.processItem)
both work fine here
regards
Zoltan
Christopher M. Nahler wrote:
On 23.06.2010 09:46, Phil Thompson wrote:
On Wed, 23 Jun 2010 09:40:09 +0200, "Christopher M. Nahler"
<[email protected]> wrote:
I have problems using a signal. In the code below I create a
QListWidget
where I would like to act upon doubleClicking an item.
In the documentation I have found the signal "itemDoubleClicked".
(http://doc.qt.nokia.com/4.6/qlistwidget.html#itemDoubleClicked)
But somehow I am not using it right. What am I doing wrong?
thanks in advance
Chris
import sys
from PyQt4.QtCore import *
from PyQt4.QtGui import *
itemList = ["One",
"Two",
"Three",
"Four",
"Five"]
class ListDlg(QDialog):
def __init__(self, name, parent=None):
super(ListDlg, self).__init__(parent)
self.myList = QListWidget()
self.myList.addItems(itemList)
self.myList.setCurrentRow(0)
layout = QHBoxLayout()
layout.addWidget(self.myList)
self.setLayout(layout)
self.connect(self.myList,
SIGNAL("itemDoubleClicked(*item)"),
self.processItem)
def processItem(self, item):
print(item.text())
if __name__ == "__main__":
app = QApplication(sys.argv)
form = ListDlg("Listdialog")
form.exec_()
The signal signature is "itemDoubleClicked(QListWidgetItem *)"
Phil
The way I understand this is that the signal passes a pointer to an
item, right? So what is the correct way to setup the connection? I have
tried with SIGNAL("itemDoubleClicked(item*)" and
SIGNAL("itemDoubleClicked(item *)" but that also did not work.
_______________________________________________
PyQt mailing list [email protected]
http://www.riverbankcomputing.com/mailman/listinfo/pyqt
