Attached correct version of test.py **** (Still doesn't work, but uses
numpy arrays in the scatter plot inputs).
On Monday, 5 April 2021 at 09:11:11 UTC-3 Kevin Dunphy wrote:
>
> This isn't quite my problem. I've attached some test scripts that show
> where the error occurs. The only major difference in that in one case I am
> embedding the GL widget into a main window, and in another case I am not. I
> don't think it is a driver issue *because* test2.py works without issues.
>
> For context, I am running the following versions:
>
> Python 3.8
> PyQt5 5.15.1
> pyqtgraph 0.12.0
> numpy 1.19.4
>
> On Monday, 5 April 2021 at 00:06:47 UTC-3 Nit wrote:
>
>> Hi, you might need to place the place the graphicsview inside gridlayout,
>> add GLviewwidget onto the layout
>>
>> #Create object form GLviewWidget
>> self.viewt = gl.GLViewWidget()
>> #create grid features
>> self.xgrid.rotate(90, 0, 1, 0)
>> self.xgrid.translate(-10, 0, 0)
>> #add grid item to GLviewWidget object
>> self.viewt.addItem(self.xgrid)
>>
>> #This should solve the issue
>> self.layout_parent = QGridLayout(self.graphicsView)
>> self.layout_parent.setContentsMargins(20, 20, 20, 20)
>> self.layout_parent.addWidget(self.viewt)
>>
>> Let me know
>>
>> On Sunday, April 4, 2021 at 6:31:19 AM UTC-7 [email protected] wrote:
>>
>>> Hello everyone,
>>>
>>> I'm fairly new to PyQtGraph, and for the most part I have been having
>>> tremendous success. I am creating an application that does some analysis on
>>> objects in 3D space, and generates plots based on their geometry. Currently
>>> my plots are all 2D, with an image view and linked axes to show data
>>> arising from the underlying model geometry, however I was hoping to also
>>> include a 3D plot *showing* the geometry. Going through the PyQtGraph
>>> examples, the GlScatterPlotItem looks to be precisely what I am looking for.
>>>
>>> Oddly enough, the example runs perfectly fine, however when I try to
>>> implement this into my application I got an error. My first instinct was to
>>> bring the GlViewWidget outside of my GraphicsLayoutWidget, and plot
>>> independently. This worked.. kind of. I can add a GridItem to the
>>> GlViewWidget, and that renders fine - I can interact with it as I can in
>>> the examples. However, upon trying to add a GlScatterPlotItem I get the
>>> following error:
>>>
>>> line 114, in addItem
>>> self.checkOpenGLVersion('Error while adding item %s to
>>> GLViewWidget.' % str(item))
>>>
>>> line 535, in checkOpenGLVersion
>>> verString = glGetString(GL_VERSION)
>>>
>>> line 415, in __call__
>>> return self( *args, **named )
>>>
>>> line 230, in glCheckError
>>> raise self._errorClass(
>>> OpenGL.error.GLError: GLError(
>>> err = 1282,
>>> description = b'invalid operation',
>>> baseOperation = glGetString,
>>> cArguments = (GL_VERSION,)
>>> )
>>>
>>> What baffles me is that the examples work without issue. Some googling
>>> lead me to upgrading mesa drivers, however that did not seem to fix the
>>> issue - Any ideas on what I could do to make this work?
>>>
>>>
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from PyQt5 import QtWidgets, uic
import pyqtgraph.opengl as gl
import pyqtgraph as pg
import numpy as np
class MainWindow(QtWidgets.QMainWindow):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
uic.loadUi('test.ui', self)
self.openGLWidget.show()
def main():
m = MainWindow()
grid = gl.GLGridItem()
m.openGLWidget.addItem(grid) # <-- Works, no problem.
pos = np.array([(0, 0, 0), (0, 1, 0)])
size = np.array([10, 10])
scatter_plot = gl.GLScatterPlotItem(pos=pos, size=size)
m.openGLWidget.addItem(scatter_plot) # <-- Throws error
if __name__ == '__main__':
app = pg.mkQApp()
main()
pg.mkQApp().exec_()
