On 9/3/05, Nick Coghlan <[EMAIL PROTECTED]> wrote: [...] > Playing well with generator expressions comes for free, too: > > print " ".join(str(x*x) for x in range(10)) > => output(*(x*x for x in range(10)))
Hmm... This prompts a coding question - is it possible to recognise which arguments to a function are generators, so that you could write output(1, 2, [3,4], (c for c in 'abc'), 'def', (5, 6)) and get 1 2 [3, 4] a b c def (5, 6) ? At the simplest level, an explicit check for types.GeneratorType would work, but I'm not sure if there's a more general check that might might work - for example, iter((1,2,3)) may be a candidate for looping over, where (1,2,3) clearly (? :-)) isn't. Maybe "iter(arg) is arg" is the right check... Of course, there's a completely separate question as to whether magic this subtle is *advisable*... Paul. _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com