For clarity, I'll change
If ``s`` does not have ``pre`` as a prefix, an unchanged copy of ``s`` is
returned.
to
If ``s`` does not have ``pre`` as a prefix, then ``s.cutprefix(pre)``
returns ``s`` or an unchanged copy of ``s``.
For consistency with the Specification section, I'll also change
s[len(pre):] if s.startswith(pre) else s
to
s[len(pre):] if s.startswith(pre) else s[:]
and similarly change the ``cutsuffix`` snippet.
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