On 2020-03-20 21:49, Dennis Sweeney wrote:
For clarity, I'll change
If ``s`` does not have ``pre`` as a prefix, an unchanged copy of ``s`` is
returned.
to
If ``s`` does not have ``pre`` as a prefix, then ``s.cutprefix(pre)``
returns ``s`` or an unchanged copy of ``s``.
For consistency with the Specification section, I'll also change
s[len(pre):] if s.startswith(pre) else s
to
s[len(pre):] if s.startswith(pre) else s[:]
and similarly change the ``cutsuffix`` snippet.
If ``s`` is immutable, why return a copy when the original will do?
s[len(pre) : ] if pre and s.startswith(pre) else s
s[ : -len(suf)] if suf and s.endswith(suf) else s
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