Brett Cannon wrote:
Taking a new argument that has a default shouldn't be an issue. +1 from me. I assume it is just going to start the count at that number, not advance the iterable to that point, right?
I wonder if it would be best for it to be a keyword-only argument. So many of the utility functions on iterables are foo(*iterables) that I might be inclined to think enumerate(foo, bar) is equivalent to enumerate(chain(foo, bar)), but enumerate(foo, start=bar) is pretty obvious. And if you consider that the enumeration is prepended to the values of foo, enumerate(foo, bar) is "backwards." Just saying.. -Scott -- Scott Dial [EMAIL PROTECTED] [EMAIL PROTECTED] _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
