+1 to this. On Sun, May 11, 2008 at 6:23 PM, Scott Dial <[EMAIL PROTECTED]> wrote: > Brett Cannon wrote: >> >> Taking a new argument that has a default shouldn't be an issue. +1 >> from me. I assume it is just going to start the count at that number, >> not advance the iterable to that point, right? > > I wonder if it would be best for it to be a keyword-only argument. So > many of the utility functions on iterables are foo(*iterables) that I > might be inclined to think enumerate(foo, bar) is equivalent to > enumerate(chain(foo, bar)), but enumerate(foo, start=bar) is pretty > obvious. And if you consider that the enumeration is prepended to the > values of foo, enumerate(foo, bar) is "backwards." Just saying.. > > -Scott > > -- > Scott Dial > [EMAIL PROTECTED] > [EMAIL PROTECTED] > > _______________________________________________ > Python-Dev mailing list > Python-Dev@python.org > http://mail.python.org/mailman/listinfo/python-dev > Unsubscribe: > http://mail.python.org/mailman/options/python-dev/guido%40python.org >
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