Paul Moore wrote:
On 03/07/2008, Guido van Rossum <[EMAIL PROTECTED]> wrote:
I don't see an answer there to the question of whether the length()
method of a Java String object containing a single surrogate pair
returns 1 or 2; I suspect it returns 2.
It appears you're right:
type testucs.java
class testucs {
public static void main(String[] args) {
StringBuilder s = new StringBuilder("Hello, ");
s.appendCodePoint(0x2F81A);
System.out.println(s); // Display the string.
System.out.println(s.length());
}
}
java testucs
Hello, ?
9
java -version
java version "1.6.0_05"
Java(TM) SE Runtime Environment (build 1.6.0_05-b13)
Java HotSpot(TM) Client VM (build 10.0-b19, mixed mode, sharing)
Python 3 supports things like
chr(0x12345) and ord("\U00012345"). (And so does Python 2, using
unichr and unicode literals.)
And Java doesn't appear to - that appendCodePoint() method was
wonderfully hard to find :-)
There's also the issue of indexing the Unicode strings. If we are going
to insist that len(u) counts surrogate pairs as one character then
random access to the characters of a string is going to be an extremely
inefficient operation.
Surely it's desirable under all circumstances that
len(u) == sum(1 for c in u)
and that
[c for c in u] == [c[i] for i in range(*len(u))]
How would that play under Jeroen's proposed change?
regards
Steve
--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/
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