John Arbash Meinel wrote:
res = heads(node1, node2)
if len(res) == 1:
# What is the 'obvious' way to get the node out?
I posit that there *isn't* an obvious way to get the single item out of
a 1-entry frozenset.
for x in res: break
list(res)[0]
set(res).pop()
iter(res).next()
[x for x in res][0]
x, = res # I didn't think of this one before recently
Are all answers, but none of them I would consider *obvious*.
And from my SQL-hacking experience:
x = min(s)
--Scott David Daniels
scott.dani...@acm.org
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