Robert Kern wrote:
On 4/28/11 8:44 PM, Steven D'Aprano wrote:
Greg Ewing wrote:
Taking a step back from all this, why does Python allow
NaNs to arise from computations *at all*?
The real question should be, why does Python treat all NANs as
signalling NANs
instead of quiet NANs? I don't believe this helps anyone.
Actually, Python treats all NaNs as quiet NaNs and never signalling NaNs.
Sorry, did I get that backwards? I thought it was signalling NANs that
cause a signal (in Python terms, an exception)?
If I do x = 0.0/0 I get an exception instead of a NAN. Hence a
signalling NAN.
--
Steven
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