The bin/python3 executable in a framework is a small stub that
execv's the real interpreter that is stuffed in a Python.app bundle
inside the Python framework. That's done to ensure that GUI code can
work from the command-line, Apple's GUI framework refuse to work when
the executable is not in an application bundle.
Because of this trick pyvenv won't know which executable the user
actually called and hence cannot find the pyvenv configuration file
(which is next to the stub executable).
I don't understand. The "executable that the user actually called":
does that refer to
a) the stub (which the user *actually* called) or
b) the eventual binary (which is what gets *actually* run).
If a), then I think argv[0] just needs to continue to refer to the
stub, which is easy to achieve in execv.
If b), I wonder why the code needs to know the location to the binary
inside the bundle. But if this is needed to know, I suggest that some
environment variable is passed from the stub to the actual binary
(akin PYTHONHOME). How does the stub normally find out where the
framework is located?
Regards,
Martin
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