On 5/20/2012 4:31 AM, nick.coghlan wrote:
+ and ``x.__hash__()`` returns an appropriate value such that ``x == y`` + implies both that ``x is y`` and ``hash(x) == hash(y)``.
I don't understand what you were trying to say with x == y implies x is y but I know you know that that is not true ;=0. _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
