It's true for the default comparison definition for user defined classes, which is what that paragraph describes.
-- Sent from my phone, thus the relative brevity :) On May 21, 2012 2:32 AM, "Terry Reedy" <tjre...@udel.edu> wrote: > On 5/20/2012 4:31 AM, nick.coghlan wrote: > > + and ``x.__hash__()`` returns an appropriate value such that ``x == y`` >> + implies both that ``x is y`` and ``hash(x) == hash(y)``. >> > > I don't understand what you were trying to say with > x == y implies x is y > but I know you know that that is not true ;=0. > > ______________________________**_________________ > Python-Dev mailing list > Python-Dev@python.org > http://mail.python.org/**mailman/listinfo/python-dev<http://mail.python.org/mailman/listinfo/python-dev> > Unsubscribe: http://mail.python.org/**mailman/options/python-dev/** > ncoghlan%40gmail.com<http://mail.python.org/mailman/options/python-dev/ncoghlan%40gmail.com> >
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