On 10/09/2013 03:57 AM, Joao S. O. Bueno wrote:
def a([b],/,**kw):
print (b)
does calling "a(b=5)" should raise a TypeError, or put "5" in
"""kw["b"]""" and leave
"b" as "undefined" ?
The latter. This is how they are "similarly to *args and **kwargs":
>>> def foo(*a, **kw):
... print(a, kw)
...
>>> foo(a=3, kw=5)
() {'kw': 5, 'a': 3}
>>>
//arry/
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