inspect.getargspec(method) and inspect.signature(method) both include the
'self' parameter but how are we to figure out from method itself that it is
actually bound and that its first parameter is expected to be a bound
instance?
So far I've come up with:
*inspect.ismethod(method) or inspect.ismethoddescriptor(method)*
But that is still not quite right as it remains False in 3.4 for the simple
case of:
>>> class A:
... def x(self):
... pass
...
>>> inspect.ismethod(A.x)
False
>>> inspect.ismethoddescriptor(A.x)
False
>>> inspect.signature(A.x).parameters
mappingproxy(OrderedDict([('self', <Parameter at 0x7fdd8188eae8 'self'>)]))
>>> inspect.getargspec(A.x)
ArgSpec(args=['self'], varargs=None, keywords=None, defaults=None)
The above works if use it on object.__init__, but not on a method of an
uninstantiated class. (it also works on the instantiated A().x)
Checking if *(inspect.isfunction(method) and method.__qualname__ !=
method.__name__)* perhaps but that seems questionably hacky. Is there a
right way to do this via the inspect module that I've missed?
It seems like that'd be nice, but I don't feel like I know enough to write
up a feature request for it yet. (granted I hope nobody *wants* to write
code that does this...)
-gps
_______________________________________________
Python-Dev mailing list
Python-Dev@python.org
https://mail.python.org/mailman/listinfo/python-dev
Unsubscribe:
https://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
