On 2/24/2015 8:56 PM, Gregory P. Smith wrote:
inspect.getargspec(method) and inspect.signature(method) both include
the 'self' parameter but how are we to figure out from method itself
that it is actually bound and that its first parameter is expected to be
a bound instance?
This seems like a python-list question.
So far I've come up with:
/inspect.ismethod(method) or inspect.ismethoddescriptor(method)/
But that is still not quite right as it remains False in 3.4 for the
simple case of:
>>> class A:
... def x(self):
... pass
...
>>> inspect.ismethod(A.x)
False
>>> inspect.ismethoddescriptor(A.x)
False
These are correct. A.x is the function resulting from execution of the
def statement.
>>> type(A.x)
<class 'function'>
This is different from 2.x. If you call the function as a function,
there is no requirement on its argument, and no binding.
>>> A.x(3) # returns None
>>>
--
Terry Jan Reedy
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