On Tue, Oct 18, 2016, at 04:01, Daniel Moisset wrote:
> I see some mention that flatten does not cover all cases; but correct
> me if I'm wrong with this statement:
> Any case of [*<exp1> for <vars> in <exp2>] could be replaced with
> flatten(<exp1> for <vars> in <exp2>). Where flatten is defined as
> def flatten(it):
>     return [x for for subit in it for x in subit]

That is correct - though flatten as previously discussed did not return
a list, so list(flatten(...)) was required, though I suppose you could
use [*flatten(...)] - my point was that [especially with the list
constructor] this is significantly more verbose than the proposed
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