>
> def foo():
> a, b, c = 1, 2, 3
> function(a=77, **use('b d'))
>
> foo()
> You get the output “77 None 33 None”. So basically it doesn’t work at all.
> For the reason I wrote clearly in my last mail. You have to dig through the
> stack frames to make use() work.
>
OK, you are right. Improved implementation. Still not very hard.
In any case, I'm concerned with the API to *use* the `use()` function, not
how it's implemented. The point is really just that we can accomplish the
same thing you want without syntax added.
>>> import inspect
>>> def reach(name):
... for f in inspect.stack():
... if name in f[0].f_locals:
... return f[0].f_locals[name]
... return None
...
>>> def use(names):
... kws = {}
... for name in names.split():
... kws[name] = reach(name)
... return kws
...
>>> def function(a=11, b=22, c=33, d=44):
... print(a, b, c, d)
...
>>> function(a=77, **use('b d'))
77 None 33 None
>>> def foo():
... a, b, c = 1, 2, 3
... function(a=77, **use('b d'))
...
>>> foo()
77 2 33 None
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