> items = ["foo", "bar", "quux"]
> items[randrange(3)] .= upper()
>
> Is this equivalent to:
>
> items[randrange(3)] = items[randrange(3)].upper()
>
> ? That would call randrange twice, potentially grabbing one element
> and dropping it into another slot. If it isn't equivalent to that, how
> is it defined?
It would not call randrange twice. Consider existing Python behavior:
def foo():
print("foo")
return 0
l = [7]
l[foo()] += 1
# output: "foo", but only once
print(l) # l == [8]
Sent from my iPhone
> On Sep 27, 2018, at 4:13 PM, Chris Angelico <ros...@gmail.com> wrote:
>
> That would call randrange twice, potentially grabbing one element
> and dropping it into another slot. If it isn't equivalent to that, how
> is it defined?
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