TITLE: output debug information easily and quickly POSSIBLE SOLUTION
Short form of keyword arguments where foo(=a, =1+bar) Is expanded at compile time to foo(**{'a': a, '1+bar': 1+bar}) Then we can just create a normal debug function: def debug_print(**vars): for k, v in vars.items(): print(f'{k}={v}') this is of course useful for many other things as Steven has pointed out. / Anders _______________________________________________ Python-ideas mailing list Python-ideas@python.org https://mail.python.org/mailman/listinfo/python-ideas Code of Conduct: http://python.org/psf/codeofconduct/