>> foo(=a, =1+bar)
>
> Unfortunately, that won't help with Jonathan's inital example
> expression "big_array[5:20]" as it's not a valid keyword.
I didn't understand that. The example you are referring to is
print('big_array[5:20] =', big_array[5:20])
Right?
Nothing is a keyword in that example or in my example. My suggestion is that we
could do:
my_func(=big_array[5:20])
And it would be compile time transformed into
my_func(**{'big_array[5:20]': big_array[5:20]})
and then my_func is just a normal function:
def my_func(**kwargs):
Whatever
It's a very simple textual transformation.
/ Anders
_______________________________________________
Python-ideas mailing list
Python-ideas@python.org
https://mail.python.org/mailman/listinfo/python-ideas
Code of Conduct: http://python.org/psf/codeofconduct/
