I think the same way about set.pop, list.pop.
About .index I agree adding default= would make sense but that's not
exactly the same thing as the others.
Do we have somewhere else a place where a linear search already accepts a
default= kwarg ?
def index(self, x):
for i,y in enumerate(self):
if x == y:
return i
raise ValueError
We do have "next", the default version of .index is currently implentable
as :
next((i for i, y in enumerate(self) if x == y), -1)
If I want -1 for default.
Le mer. 31 oct. 2018 à 10:23, Nicolas Rolin <nicolas.ro...@tiime.fr> a
écrit :
>
> As a user I always found a bit disurbing that dict pop method have a
> default while list and set doesn't.
> While it is way more computationally easy to check wether a list or a set
> is empty that to check if a key is in a dict, it still create a signature
> difference for no real reason (having a default to a built-in in python is
> pretty standard).
> It would be nice if every built-in/method of built-in type that returns a
> value and raise in some case have access to a default instead of raise, and
> not having to check the doc to see if it supports a default.
>
> We could for exemple ask ourselves wether or not list.index should have a
> default, as it is a method that we explecitely excpect to return a value
> and might just raise instead.
>
> 2018-10-31 2:08 GMT+01:00 Steven D'Aprano <st...@pearwood.info>:
>
>> On Wed, Oct 31, 2018 at 02:25:25AM +0200, Serhiy Storchaka wrote:
>> > 31.10.18 01:44, Giampaolo Rodola' пише:
>> > >Sorry in advance if this has been proposed in the past but I couldn't
>> > >find anything on python-ideas:
>> > >
>> > > >>> l = []
>> > > >>> l.pop(default=1)
>> > >1
>> [...]
>>
>> > It is just
>> >
>> > l.pop() if l else default
>>
>> It might *do* the same thing, but it doesn't communicate the
>> programmer's intention as well.
>>
>> {}.pop('key', default) could be written using LBYL too, but the
>> intention is much clearer given an explicit default argument.
>>
>> The only advantage of the "if l" version is that if the default is
>> expensive to calculate, we can short-circuit it.
>>
>>
>> > or
>> >
>> > (l or [default]).pop()
>>
>> That's clever, but it is also wasteful, building a single-item list only
>> to immediately pop the item out of it and throw the list away.
>>
>> [steve@ando ~]$ python3.5 -m timeit -s "l = []" "l.pop() if l else None"
>> 10000000 loops, best of 3: 0.0739 usec per loop
>>
>> [steve@ando ~]$ python3.5 -m timeit -s "l = []" "(l or [None]).pop()"
>> 1000000 loops, best of 3: 0.421 usec per loop
>>
>>
>>
>> --
>> Steve
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>
>
>
> --
>
> --
> *Nicolas Rolin* | Data Scientist
> + 33 631992617 - nicolas.ro...@tiime.fr <prenom....@tiime.fr>
>
>
> *15 rue Auber, **75009 Paris*
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