I was writing some python code earlier, and I noticed that in a code that
looks somwhat like this one :
try:
i = int("string")
print("continued on")
j = int(9.0)
except ValueError as e:
print(e)
>>> "invalid literal for int() with base 10: 'string'"
this code will handle the exception, but the code in the try block will not
continue.
I propose to be able to use the continue keyword to continue the execution
of the try block even when an error is handled. The above could then be
changed to :
try:
i = int("string")
print("continued on")
j = int(9.0)
except ValueError as e:
print(e)
continue
>>> "invalid literal for int() with base 10: 'string'"
>>> "continued on"
_______________________________________________
Python-ideas mailing list
Python-ideas@python.org
https://mail.python.org/mailman/listinfo/python-ideas
Code of Conduct: http://python.org/psf/codeofconduct/
