On 1/5/19 7:38 PM, Simon wrote:
>
> I was writing some python code earlier, and I noticed that in a code
> that looks somwhat like this one :
>
> try:
> i = int("string")
> print("continued on")
> j = int(9.0)
> except ValueError as e:
> print(e)
>
> >>> "invalid literal for int() with base 10: 'string'"
>
> this code will handle the exception, but the code in the try block
> will not continue.
>
> I propose to be able to use the continue keyword to continue the
> execution of the try block even when an error is handled. The above
> could then be changed to :
>
>
> try:
> i = int("string")
> print("continued on")
> j = int(9.0)
> except ValueError as e:
> print(e)
> continue
>
> >>> "invalid literal for int() with base 10: 'string'"
> >>> "continued on"
>
How would you tell it where to continue? Why would it be the next
statement? If you want that then you just need to do it like:
try:
i = int("string")
except ValueError as e:
print(e)
print("continued on")
j = int(9.0)
i.e. the try block is the program segment that either executes
successful, or your exception routine recovers from the error and sets
things up to continue from there.
--
Richard Damon
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