Beyond possibly saving 3-5 characters, I continue not to see anything
different from map in this discussion.
list(vector) applies list to the vector itself.
> list.(vector) applies list to each component of vector.
>
In Python:
list(seq) applies list to the sequence itself
map(list, seq) applies list to each component of seq
In terms of other examples:
map(str.upper, seq) uppercases each item
map(operator.attrgetter('name'), seq) gets the name attribute of each item
map(lambda a: a*2, seq) doubles each item
(lambda a: a*2)(seq) doubles the sequence itself
... Last two might enjoy named function 'double'
> > The problem, of course, is that list() now has to understand Vector
> > specially, and so does any function you think of applying to it.
>
> *The whole point* of the Julia syntax is that no function has to
> understand any sequence. When we write:
>
> for item in vector:
> func(item)
>
> func only has to understand item, not vector. The same applies to the
> Julia syntax
>
> func.(vector)
>
> There's no puzzle here, no tricky cases, because it is completely
> deterministic and explicit: func(x) always calls func with x as
> argument, func.(x) always calls func with each of x's items as
> arguments.
>
>
>
> > Operators are easier (even those like [1:]) because Vector can make its
> > own definition of each through (a finite set of) dunder methods. To make
> > a Vector accept an arbitrarily-named method call like my_strings.upper()
> > to mean:
>
> With the Julia syntax, there is no need for vectors (or lists, or
> generators, or tuples, or sets, or any other iterator...) to accept
> arbitrary method calls. So long as vectors can be iterated over,
> func.(vector) will work.
>
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