It might also be worth considering YAML's own dict merge operator, the "<<" operator, as in https://yaml.org/type/merge.html as this is the existing Python's shift operator added to dict and will require no change to the synatx::
a = a << b Meitham On 03/10, Chris Angelico wrote: > On Sun, Mar 10, 2019 at 3:16 AM Jonathan Fine <jfine2...@gmail.com> wrote: > > > > Anders Hovmöller wrote: > > > > > I don't understand what you mean. Can you provide examples that show the > > > state of the dicts before and after and what the syntax would be the > > > equivalent of in current python? > > > > If a.__radd__ exists, then > > a += b > > is equivalent to > > a = a.__radd__(b) > > > > Similarly, if a.__iat_update__ exists then > > a @update= b > > would be equivalent to > > a = a.__iat_update__(b) > > > > Here's an implementation > > def __iat_update__(self, other): > > self.update(other) > > return self > > > > Thus, 'b' would be unchanged, and 'a' would be the same dictionary as > > before, but updated with 'b'. > > With something this long, how is it better from just writing: > > a = a.update_with(b) > > ? What's the point of an operator, especially if - by your own > statement - it will backward-incompatibly change the language grammar > (in ways that I've yet to understand, since you haven't really been > clear on that)? > > ChrisA > -- Meitham Jamaa http://meitham.com GPG Fingerprint: 3934D0B2
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