>> Does that mean that first() and next() are undefined for sets?
[Stephen J. Turnbull <turnbull.stephen...@u.tsukuba.ac.jp>]
> first() is undefined. next() is defined by reference to iterating
> over the set (that's why I don't have a problem with iterating over a
> set).
Every suggestion here so far has satisfied that, if S is a non-empty set,
assert next(iter(S)) is first(S)
succeeds. That is, `first()` is _defined_ by reference to iteration
order. It's "the first" in that order (hence the name).
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