How would the interpreter know which
Class the rebound “belonged” to?
For example, that same function could be added to two different classes—
then what would super() do?
BTW, the Python 2 style of calling súper with the class and instance as
arguments might work in the case :-)
As an experiment, try adding the placement method to a different class
altogether and see what you get.
class another:
foo = child.placement
-CHB
On Tue, Jul 27, 2021 at 8:16 PM Yua <unch...@163.com> wrote:
> For example, the following code would report an error:
>
> class base():
> def foo(self) -> None:
> print('Base!')
>
> def placement(self) -> None:
> super().foo()
>
> class child(base):
> def foo(self) -> None:
> pass
> foo = placement
>
> child().foo()
>
> RuntimeError: super(): __class__ cell not found
>
>
> However, it would be OK if `placement` is defined inside the class:
>
> class base():
> def foo(self) -> None:
> print('Base!')
>
> class child(base):
> def placement(self) -> None:
> super().foo()
> def foo(self) -> None:
> pass
> foo = placement
>
> child().foo()
>
> which prints:
>
> Base!
>
>
> I think it would be natural if those functions that was defined outside
> a class, but then rebound into a class, can see magic variables like
> __class__ that are only shared by those functions defined inside a class.
>
>
> Thank you!
>
>
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--
Christopher Barker, PhD (Chris)
Python Language Consulting
- Teaching
- Scientific Software Development
- Desktop GUI and Web Development
- wxPython, numpy, scipy, Cython
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