Oh I forgot what if you want to return a set from your lambda? Maybe a lambda
set should at least have one assignment statement to qualify it as one.
Expressions only inside a set syntax will be just a normal set that doesn’t
care about order as you pointed out. But a lambda set will care about the order
just like when you do a normal multi-lines def function.
def f(x):
print(x)
z = x + 3
return z
Is equivalent to
(x) => {print(x), z = x + 3, z}
since “z = x + 3” is an assignment statement, this would be qualified as a
lambda set. Normal set will not be possible as that will throw syntax error. So
the side effect is a printed x and the return is just z.
If you write something like the following:
(x) => {print(x), x +3}
Make x = 1 and the return value will be just a normal set of {None, 4} or {4,
None} with a printed 1 as a side effect.
Abdulla
Sent from my iPhone
> On 3 Oct 2021, at 8:29 PM, Eric Fahlgren <ericfahlg...@gmail.com> wrote:
>
>
> I'm somewhat confused by the term "last item of the set", as sets are not
> ordered and have no "last" element:
>
> >>> {1,3,3,2}
> {1, 2, 3}
>
>> On Sat, Oct 2, 2021 at 8:23 PM Abdulla Al Kathiri
>> <alkathiri.abdu...@gmail.com> wrote:
>> Then use it with the normal expression lambda:
>> people.sort(key=p => (p.salary, p.name, p.id)).
>> You don’t need lambda set for that. If you want to use it, it will be like
>> the following:
>> people.sort(key=p => {(p.salary, p.name, p.id)}). The tuple expression is
>> the last item of the set, so the tuple is the return value.
>> Abdulla
>>
>> Sent from my iPhone
>>
>> > On 3 Oct 2021, at 2:25 AM, Chris Angelico <ros...@gmail.com> wrote:
>> >
>> > people.sort(key=lambda p: (p.salary, p.name, p.id))
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