On Sun, 8 Jan 2023 at 03:44, Steven D'Aprano <st...@pearwood.info> wrote:
>
> Keep it nice and simple: provided with multiple separators, `partition`
> will split the string on the first separator found in the source string.
>
> In other words, `source.partition(a, b, c, d)` will split on a /or/ b
> /or/ c /or/ d, whichever comes first on the left.
Thanks - that's a valid and similar proposal -- partition-by-any-of --
although it's not the suggestion that I had in mind.
Roughly speaking, the goal I had in mind was to take an input that
contains well-defined delimiters in a known order and to produce a
sequence of partitions (and separating delimiters) from that input.
(you and dn have also indirectly highlighted a potential problem with
the partitioning algorithm: how would "foo?a=b&c" partition when using
'str.partition("?", "#")'? would it return a tuple of length five?)
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