> On 8 Jan 2023, at 10:10, James Addison via Python-ideas
> <python-ideas@python.org> wrote:
>
> On Sun, 8 Jan 2023 at 03:44, Steven D'Aprano <st...@pearwood.info> wrote:
>>
>> Keep it nice and simple: provided with multiple separators, `partition`
>> will split the string on the first separator found in the source string.
>>
>> In other words, `source.partition(a, b, c, d)` will split on a /or/ b
>> /or/ c /or/ d, whichever comes first on the left.
>
> Thanks - that's a valid and similar proposal -- partition-by-any-of --
> although it's not the suggestion that I had in mind.
>
> Roughly speaking, the goal I had in mind was to take an input that
> contains well-defined delimiters in a known order and to produce a
> sequence of partitions (and separating delimiters) from that input.
>
> (you and dn have also indirectly highlighted a potential problem with
> the partitioning algorithm: how would "foo?a=b&c" partition when using
> 'str.partition("?", "#")'? would it return a tuple of length five?)
Maybe combine the ideas by allowing a tuple where a string is used.
'a=b'.partition(('=', ':')) => ('a', '=', 'b')
'a:b'.partition(('=', ':')) => ('a', ':', 'b')
'a=b:c'.partition('=', (':',';')) => ('a', '=', b, ':', 'c')
'a=b;c'.partition('=', (':',';')) => ('a', '=', b, ';', 'c')
Barry
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