"Karl Kofnarson" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Hi, > while writing my last program I came upon the problem > of accessing a common local variable by a bunch of > functions. > I wanted to have a function which would, depending on > some argument, return other functions all having access to > the same variable. An OO approach would do but why not > try out closures... > So here is a simplified example of the idea: > def fun_basket(f): > common_var = [0] > def f1(): > print common_var[0] > common_var[0]=1 > def f2(): > print common_var[0] > common_var[0]=2 > if f == 1: > return f1 > if f == 2: > return f2
Karl, Usually when using this idiom, fun_basket would return a tuple of all of the defined functions, rather than one vs. the other. So in place of: > if f == 1: > return f1 > if f == 2: > return f2 Just do > return f1, f2 (For that matter, the argument f is no longer needed either.) Then your caller will get 2 functions, who share a common var. You don't call fun_basket any more, you've already created your two "closures". Call fun_basket using something like: z1,z2 = fun_basket(None) And then call z1() and z2() at your leisure - they should have the desired behavior. -- Paul -- http://mail.python.org/mailman/listinfo/python-list
