On Mar 24, 5:59 am, "Dustan" <[EMAIL PROTECTED]> wrote: > On Mar 23, 1:30 pm, Paulo da Silva <[EMAIL PROTECTED]> wrote: > > > Mike Kent escreveu: > > ... > > > > New way: > > > l=['a','b','c'] > > > jl=','.join(l) > > > I thank you all. > > > Almost there ... > > I tried "".join(l,',') but no success ... :-( > > > Paulo > > Perhaps you're doing it wrong, despite having an example right in > front of you? > > Side by side comparison: > jl=string.join(l,',') > jl=','.join(l) > > The sequence is passed as an argument to the join method, and the > delimiter is the string whose method is being called.
To further demonstrate (because I got a weird email that seemed to think that my code didn't work): >>> import string >>> l = ['a','b','c'] >>> string.join(l,',') 'a,b,c' >>> ','.join(l) 'a,b,c' -- http://mail.python.org/mailman/listinfo/python-list