import string
def test_join(l):
print "Joining with commas: ", string.join(l,',')
print "Joining with empty string: ", string.join(l,'')
print "Joining same way, using another syntax: ", ''.join(l)
print "Joining with the letter X: ", 'X'.join(l)
print "Joining with <-> ", '<->'.join(l)
l = ['a','b','c']
test_join(l)
"""
Example output:
Joining with commas: a,b,c
Joining with empty string: abc
Joining same way, using another syntax: abc
Joining with the letter X: aXbXc
Joining with <-> a<->b<->c
"""
Dustan wrote:
On Mar 24, 5:59 am, "Dustan" <[EMAIL PROTECTED]> wrote:
On Mar 23, 1:30 pm, Paulo da Silva <[EMAIL PROTECTED]> wrote:
Mike Kent escreveu:
...
New way:
l=['a','b','c']
jl=','.join(l)
I thank you all.
Almost there ...
I tried "".join(l,',') but no success ... :-(
Paulo
Perhaps you're doing it wrong, despite having an example right in
front of you?
Side by side comparison:
jl=string.join(l,',')
jl=','.join(l)
The sequence is passed as an argument to the join method, and the
delimiter is the string whose method is being called.
To further demonstrate (because I got a weird email that seemed to
think that my code didn't work):
import string
l = ['a','b','c']
string.join(l,',')
'a,b,c'
','.join(l)
'a,b,c'
--
Shane Geiger
IT Director
National Council on Economic Education
[EMAIL PROTECTED] | 402-438-8958 | http://www.ncee.net
Leading the Campaign for Economic and Financial Literacy
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email;internet:[EMAIL PROTECTED]
title:IT Director
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version:2.1
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