On Jul 27, 8:55 pm, Larry Bates <[EMAIL PROTECTED]> wrote: > josh logan wrote: > > Hello, > > > I need a round function that _always_ rounds to the higher integer if > > the argument is equidistant between two integers. In Python 3.0, this > > is not the advertised behavior of the built-in function round() as > > seen below: > > >>>> round(0.5) > > 0 > >>>> round(1.5) > > 2 > >>>> round(2.5) > > 2 > > > I would think this is a common need, but I cannot find a function in > > the Python library to do it. I wrote my own, but did I miss such a > > method in my search of the Python library? > > > Thanks > > I think what you want is something like: > > math.ceil(x-0.4999999999999) > > -Larry- Hide quoted text - > > - Show quoted text -
The version I learned back in my FORTRAN days was: int(x + 0.5) -- Paul -- http://mail.python.org/mailman/listinfo/python-list