On Mon, 18 Aug 2008 18:04:32 +0200, Peter Otten wrote: > This works just like a < b < c: > >>>> 3 in [3] and [3] == True > False > > Peter
Interesting. I agree with the OP that it is confusing! Does this expansion really get invoked every time there is an expression of the form?? expr1 binary_op1 expr2 binary_op2 expr3 ... Seemingly, the answer is yes: >>> 3 in [3] in [[3],[4]] in [[[3],[4]],5] == [[[3],[2+2]],5] True How does this play with standard precedence rules? Dan -- http://mail.python.org/mailman/listinfo/python-list
