On Aug 18, 5:57 pm, George Sakkis <[EMAIL PROTECTED]> wrote: > I'm probably missing something obvious but I can't put my finger on > it: > > >>> (3 in [3]) == True > > True > > >>> 3 in ([3] == True) > > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > TypeError: argument of type 'bool' is not iterable > > >>> 3 in [3] == True > > False > > How/why does the last one evaluate to False ? > > George
> >>> (3 in [3]) == True The list holds an integer value of 3, you check if 3 is in that list, that is true, you then check it your answer is true... > >>> 3 in ([3] == True) True and False are keywords now and do not correspond the way you think. [3] == True or [3] == False will both answer False. Python 2.5.2 (r252:60911, Feb 21 2008, 13:11:45) [MSC v.1310 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> a = list() >>> a.append(3) >>> 3 in a True >>> if a: ... print "yay" ... yay >>> if a == True: ... print "yay" ... else: ... print "nay" ... nay > >>> 3 in [3] == True http://docs.python.org/ref[3/summary.html >>> 3 in [3] == True False >>> 3 in [3] == False False However I come a bit stuck myself, since this should just tell you that you cannot do a membership test on 3 being in a bool...but it doesn't...It should be doing the [3] == True, returning false then trying to see if 3 is in false... -- http://mail.python.org/mailman/listinfo/python-list
