Re: why cannot assign to function call

[Terry Reedy]

Joe Strout wrote:

That's not necessarily true.  If you have

  a = "par" + "rot"
  b = "parrot"

then, most likely (though it depends on how clever the compiler optimizations are), there are two different string objects containing the data "parrot".

>>> a='par'+'rot'
>>> b='parrot'
>>> a is b
True

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