On Feb 16, 12:10 pm, OdarR <olivier.da...@gmail.com> wrote:
> Hi guys,
>
> how would you do a clever find and replace, where the value replacing
> the tag
> is changing on each occurence ?
>
> ".......TAG............TAG................TAG..........TAG....."
>
> is replaced by this :
>
> ".......REPL01............REPL02................REPL03..........REPL04..."
>
> A better and clever method than this snippet should exist I hope :
>
> counter = 1
> while 'TAG' in mystring:
> mystring=mystring.replace('TAG', 'REPL'+str(counter), 1)
> counter+=1
> ...
>
> (the find is always re-starting at the string beginning, this is not
> efficient.
>
> any ideas ? thanks,
>
> Olivier
You could split on the string and interleave your new string in
between:
In [1]: def replmaker():
...: index = 0
...: while True:
...: index += 1
...: yield "REPL%02i"%index
...:
In [2]: def spliton(string, tag="TAG", sepgen=replmaker):
...: repl_iter = sepgen()
...: strlist = string.split(tag)
...: length = len(strlist)
...: for index, item in enumerate(strlist):
...: yield item
...: if index < length - 1:
...: yield repl_iter.next()
...:
In [3]: ''.join(spliton
(".......TAG............TAG................TAG..........TAG....." ))
Out[3]:
'.......REPL01............REPL02................REPL03..........REPL04.....'
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