On Feb 17, 7:18 pm, Duncan Booth <duncan.bo...@invalid.invalid> wrote:
> John Machin <sjmac...@lexicon.net> wrote:
> > def fancyrepl(tag, replfunc, input_string):
> > count = 0
> > pieces = []
> > pos = 0
> > taglen = len(tag)
> > while 1:
> > try:
> > newpos = input_string.index(tag, pos)
> > except ValueError:
> > pieces.append(input_string[pos:])
> > return ''.join(pieces)
> > pieces.append(input_string[pos:newpos])
> > count += 1
> > pieces.append(replfunc(count))
> > pos = newpos + taglen
>
> Or even:
>
> import re, itertools
> def fancyrepl(tag, replfunc, input_string):
> counter = itertools.count(1)
> return re.sub(re.escape(tag),
> lambda m: replfunc(counter.next()), input_string)
>
> which does exactly the same thing
Not exactly; mine needs
taglen = max(1, len(tag))
to stop an infinite loop when len(tag) == 0.
> in rather less code.
and with rather less execution speed [measured at about half] and
rather less OP-explanation speed [guessed] :-)
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