If I am trying to access a google scholar search result using python, I get the following error(403): $ python Python 2.7.3 (default, Jul 24 2012, 10:05:38) [GCC 4.7.0 20120507 (Red Hat 4.7.0-5)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> from HTMLParser import HTMLParser >>> import urllib2 response = urllib2.urlopen('http://scholar.google.co.uk/scholar?q=albert +einstein%2B1905&btnG=&hl=en&as_sdt=0%2C5&as_sdtp=') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib64/python2.7/urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "/usr/lib64/python2.7/urllib2.py", line 406, in open response = meth(req, response) File "/usr/lib64/python2.7/urllib2.py", line 519, in http_response 'http', request, response, code, msg, hdrs) File "/usr/lib64/python2.7/urllib2.py", line 444, in error return self._call_chain(*args) File "/usr/lib64/python2.7/urllib2.py", line 378, in _call_chain result = func(*args) File "/usr/lib64/python2.7/urllib2.py", line 527, in http_error_default raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) urllib2.HTTPError: HTTP Error 403: Forbidden >>>
Will you kindly explain me the way to get rid of this? -- http://mail.python.org/mailman/listinfo/python-list