On 10/8/2012 3:28 PM, mooremath...@gmail.com wrote:
What's the best way to accomplish this? Am I over-complicating it? My gut
feeling is there is a better way than the following:
import itertools
x = [1, 2, 3]
y = list(itertools.chain.from_iterable(('insertme', x[i]) for i in
range(len(x))))
y
['insertme', 1, 'insertme', 2, 'insertme', 3]
The straightforward, crystal-clear, old-fashioned way
>>> lst = []
>>> for item in [1,2,3]:
lst.append('insert me')
lst.append(item)
>>> lst
['insert me', 1, 'insert me', 2, 'insert me', 3]
Paul Rubin's list(gfunc(prefix, lst)) is similar in execution.
--
Terry Jan Reedy
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