On 07/18/2013 10:16 PM, CTSB01 wrote:
Does something like
def phi_m(x, m):
rtn = []
for n2 in range(0, len(x) * m - 2):
n = n2 / m
r = n2 - n * m
rtn.append(m * x[n] + r * (x[n + 1] - x[n]))
print ('n2 =', n2, ': n =', n, ' r =' , r, ' rtn =', rtn)
return rtn
look right?
No, as Ian has pointed out, you need to use the // operator in Python 3
if you want to get integer results. So it'd be n = n2 // m
However, even better is to use the divmod() function, which is intended
for the purpose:
n, r = divmod(n2, m)
It doesn't seem to have any errors. However, I do receive the following error
when trying to implement an x after having defined phi:
x = [0, 1, 1, 2, 3]
phi_m(x, 2)
Traceback (most recent call last):
File "<pyshell#6>", line 1, in <module>
phi_m(x, 2)
File "<pyshell#2>", line 6, in phi_m
rtn.append(m * x[n] + r * (x[n + 1] - x[n]))
TypeError: list indices must be integers, not float
That will be fixed if you correct the code as I described, so you'll get
integers.
There is a Brezenham algorith that might accomplish this whole function
more accurately, or more efficiently. But I'd have to re-derive it, as
it's been about 30 years since I used it. And chances are that the
efficiencies it brought to machine code won't matter much here.
--
DaveA
--
http://mail.python.org/mailman/listinfo/python-list
