On Tue, Apr 1, 2014 at 12:24 AM, David Hutto <dwightdhu...@gmail.com> wrote:
>>
>> >> (1) v = u + at
>> >> (2) s = 1/2(u + v)t
>> >> (3) s = ut + 1/2(at^2)
>> >> (4) v^2 = u^2 + 2as
>> >>
>> >> Only (1) and (3) are needed.
>> >
>> > Okay, what's u here? Heh.
>>
>> u is the initial velocity; v is the velocity after accelerating at a for
>> time t.
>
>
> This assumes that the viscosity is in a state of superfluidity, and in a
> perfect state between itself, and it's traveling environment.

I fail to see how this is relevant.  I would assume that the amount of
friction is already modeled in the acceleration constants; if it were
zero then the brakes would be nonfunctional and the train would not be
able to accelerate or decelerate at all.  In any case, a change in
friction simply works out to a change in acceleration.  The equations
above still hold true.
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