2014年6月12日木曜日 12時58分27秒 UTC+9 Chris Angelico: > On Thu, Jun 12, 2014 at 1:40 PM, Vincent Vande Vyvre > > <vincent.vandevy...@swing.be> wrote: > > > Le 12/06/2014 05:12, hito koto a écrit : > > > > > >> Hello,all > > >> I'm first time, > > >> > > >> I want to make a while statement which can function the same x.pop () and > > >> without the use of pop、how can i to do? > > >> > > >> i want to change this is code: > > >> > > >> def foo(x): > > >> y = [] > > >> while x !=[]: > > >> y.append(x.pop()) > > >> return y > > > > > > Something like that : > > > > > > def foo(x): > > > return reversed(x) > > > > That doesn't do the same thing, though. Given a list x, the original > > function will empty that list and return a new list in reverse order, > > but yours will return a reversed iterator over the original list > > without changing it. This is more accurate, but still not identical, > > and probably not what the OP's teacher is looking for: > > > > def foo(x): > > y = x[::-1] > > x[:] = [] > > return y > > > > If the mutation of x is unimportant, it can simply be: > > > > def foo(x): > > return x[::-1] > > > > ChrisA
I want to use while statement, for example: >>> def foo(x): ... y = [] ... while x !=[]: ... y.append(x.pop()) ... return y ... >>> print foo(a) [[10], [5, 6, 7, 8, 9], [1, 2, 3, 4]] >>> a [] but this is empty >>> so,I want to leave a number of previous (a = [[1, 2, 3, 4],[5, 6, 7, 8, >>> 9],[10]]) -- https://mail.python.org/mailman/listinfo/python-list
