On Thursday, June 19, 2014 1:53:31 PM UTC+8, Nicholas Cannon wrote:
> I am making a calculator and i need it to support floating point values but i 
> am using the function isnumeric to check if the user has entered an int 
> value. I need the same for floating point types so i could implement an or in 
> the if statement that checks the values the user has entered and allow it to 
> check and use floating points. If you need the source code i am happy to give 
> it to you. Thank you for your help

I am using python 2.7.7 and i have come up with away but there is still 
possible errors for this. What i did was i this

#checks if the user input is an integer value
def checkint(a):
        if a.isnumeric():
                return True
                if a.isalpha():
                        return False
                        return True

The parameter a is the users input by the raw_input function. I first test if 
it is normal int with the isnumeric function. Unfortunately this function picks 
up the decimal as false. This means if the user inputs a float it has to be 
false. I then test if this input has any alphabetical characters if it does not 
the user could have only entered  something like 12.5 oppose to abc.d. This 
method works fine and it i have  tested it and it works fine. if incase this 
input did have a letter it would be picked up by the isalpha function. There is 
one annoying error doing it this way and that is if you enter 12.ab or ab.12 it 
will say that it is okay. Still working on this so this should get sorted out 

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