On Fri, Nov 14, 2014 at 7:45 AM, Rich Cook <wealthyc...@gmail.com> wrote: > print "There are", numimages, "images" # 256 in fact... > for imagenum, (row, col) in enumerate([(row,col) for row in range(numrows) > for col in range(numcols)]): > b = Tkinter.Label(frame, compound = Tkinter.TOP) > b['text'] = os.path.basename(image_list[imagenum]) > b['image'] = ImageTk.PhotoImage(Image.open(image_list[imagenum]) )
You're asking someone somewhere to load 256 images into memory and display them. What's the resolution of these images? Do they need to be scaled/cropped? That can be fairly expensive. How long does it actually take to (a) load all those images, and (b) pack the frame? Try, for instance, commenting out the b.grid() call, to force them all to be loaded but not packed. ChrisA -- https://mail.python.org/mailman/listinfo/python-list
