On Fri, Jul 22, 2016 at 6:24 AM, Chris Angelico <ros...@gmail.com> wrote:
> On Fri, Jul 22, 2016 at 11:13 PM, Dennis Lee Bieber
> <wlfr...@ix.netcom.com> wrote:
> > Now... Going much beyond the assignment (if you were having
> trouble
> > with the assignment, this will seem like magic) [Python 2.7]:
>
> I'm not sure, but I think your code would become Py3 compatible if you
> just change your prints. Which I'd recommend - it's not difficult to
> just always print a single string, and most example code is ASCII-only
> and has no difficulty with the bytes/unicode distinction. But, point
> of curiosity...
>
> > class Refrigerator(object):
> > def __init__(self, stock=None):
> > if stock is None or type(stock) != type(dict()):
> > self._stock = dict()
> > else:
> > self._stock = stock
>
> ... why do you call up "type(dict())"? Why not either just "dict" or
> "type({})"?
>
> ChrisA
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> https://mail.python.org/mailman/listinfo/python-list
>
Hi Chris,
Try opening the interactive terminal on your command line and type the
following:
type({}) == dict()
That should illustrate why. This is because simply typing '{}' could be
interpreted as
either a dict or a set. My interpreter defaults 'type({})' to 'dict', but
it's best to not
take the risk.
You could also replace that line with:
if stock is None or type(stock) != dict:
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