Hi, in the call fp.read(8192) the function read() gets 2 arguments : <fp> and <8192>
Member functions implicitely get their object as first argument, this is why you get this error. So you have 2 possibilities : either read() doesn't take an argument anymore, or read() is not a member of fp. Anthony B. On 8/18/05, Andrey Smirnov <[EMAIL PROTECTED]> wrote: > I am getting the following traceback after upgrading my app to Python > 2.4.1. It's telling me that there is an error in Parser.py. It tells > me that 'fp.read(8192)' is given 2 arguments, but it is clearly not > true. Does anybody know what's going on here? > > Traceback (most recent call last): > File "/opt/etext/lib/python2.4/site-packages/etext/enqueue.py", line > 252, in work > worker(e.linkval, info) > File "/opt/etext/bin/etreceive", line 30, in worker > result = decode.searchfile(f) > File "/opt/etext/lib/python2.4/site-packages/etext/decode.py", line > 43, in searchfile > return Email(f) > File "/opt/etext/lib/python2.4/site-packages/etext/decode.py", line > 510, in __init__ > self.child.append(Email(mf)) > File "/opt/etext/lib/python2.4/site-packages/etext/decode.py", line > 404, in __init__ > msg = Parser().parse(f) > File "/opt/etext/lib/python2.4/email/Parser.py", line 65, in parse > data = fp.read(8192) > TypeError: read() takes exactly 1 argument (2 given) > > Thanks, > Andre. > > -- > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
